-16x^2+120x-104=0

Solution for -16x^2+120x-104=0 equation:

-16x^2+120x-104=0

a = -16; b = 120; c = -104;
Δ = b2-4ac
Δ = 1202-4·(-16)·(-104)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-88}{2*-16}=\frac{-208}{-32}
=6+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+88}{2*-16}=\frac{-32}{-32}
=1
$